Check out this with examples..
#include <stdio.h> int main() { printf( "string value\n" ); //the integer zero printf( "0.........%d\n" , 0 ); //the char zero, but chars are very small ints, so it is also an int //it just has some special syntax and conventions to allow it to seem //like a character, it's actual value is 48, this is based on the //ASCII standard, which you can look up on Wikipedia printf( "'0'.......%d\n" , '0' ); //because it is an integer, you can add it together, //'0'+'0' is the same as 48+48 , so it's value is 96 printf( "'0'+'0'...%d\n" , '0'+'0' ); //the null terminator, this indicates that it is the end of the string //this is one of the conventions strings use, as a string is just an array //of characters (in C, at least), it uses this value to know where the array //ends, that way you don't have to lug around another variable to track //how long your string is. The actual integer value of '\0' is zero. printf( "'\\0'......%d\n" , '\0' ); //as stated, a string is just an array of characters, and arrays are tracked //by the memory location of their first index. This means that a string is //actually a pointer to the memory address that stores the first element of //the string. We should get some large number, a memory address printf( "\"0\".......%d\n" , "0" ); //a string is just an array of characters, so lets access the character //in position zero of the array. it should be the character zero, which //has an integer value of 48 printf( "\"0\"[0]....%d\n" , "0"[0] ); //and the same thing for the empty string printf( "\"\\0\"[0]...%d\n" , "\0"[0] ); //equal to '\0'//we also said a string is just a pointer, so we should be able to access //the value it is pointing to (the first index of the array of characters) //by using pointers printf( "*\"0\"......%d\n" , *"0" ); return 0; }